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How much you write depends on the person and the circumstances. If you have a lot of things going on outside of sailing, you will nd that you forget things quicker and need to write more down. I think it is very important to keep a track of the settings you used in racing, as it stops you going in circles and making the same mistakes twice. I like to keep a log of the number of hours I have sailed in different conditions. If there is an imbalance, I can correct this by focusing my training on the conditions I have sailed in less. I think it is really important to write your goals down not just your overall performance goal, but also your goals for each training session. Somehow writing them down makes you commit to them more; it also means you can look back at them after a while and see what you were trying to achieve at different times in the year.

004011C0 004011C1 004011C2 004011C6 004011C8 004011CA 004011CC 004011CD 004011D3 004011D5 004011D9 004011DA 004011DC 004011E1 004011E2 004011E8 004011EA 004011EC 004011ED 004011EE 004011EF 004011F9 004011FB PUSH ECX PUSH ESI MOV ESI,SS:[ESP+C] PUSH 0 ; Origin = FILE_BEGIN PUSH 0 ; pOffsetHi = NULL PUSH 0 ; OffsetLo = 0 PUSH ESI ; hFile CALL DS:[<&KERNEL32.SetFilePointer>] PUSH 0 ; pOverlapped = NULL LEA EAX,SS:[ESP+8] PUSH EAX ; pBytesRead PUSH 28 ; BytesToRead = 28 (40.) PUSH cryptex.00406058 ; Buffer = cryptex.00406058 PUSH ESI ; hFile CALL DS:[<&KERNEL32.ReadFile>] ; ReadFile TEST EAX,EAX JNZ SHORT cryptex.004011EF POP ESI POP ECX RETN CMP DWORD PTR DS:[406058],70597243 JNZ SHORT cryptex.0040123C CMP DWORD PTR DS:[40605C],39586554

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The calculations start at the upper left corner and proceed by rst calculating the diagonal term, calculating the remaining terms in that row and column, and proceeding to the next diagonal terms. Fishman (1995) lists the algorithm, without identifying it as Cholesky decomposition. Morgan and Henrion (1990) provide a simple form for the special case that n = 2. The correlation coef cient between the two Normally distributed random variables is . If x1 and x2 are a pair of uncorrelated random numbers drawn from the

Listing 6.3 Cryptex s header-verification function that reads the Cryptex archive header and checks the supplied password.

JNZ SHORT cryptex.0040123C PUSH EDI MOV ECX,4 MOV EDI,cryptex.00405038 MOV ESI,cryptex.00406070 XOR EDX,EDX REPE CMPS DWORD PTR ES:[EDI],DWORD PTR DS:[ESI] POP EDI JE SHORT cryptex.00401234 PUSH cryptex.00403170 ; format = ERROR: password. Unable file. CALL DS:[<&MSVCR71.printf>] ; printf ADD ESP,4 PUSH 1 ; status = 1 CALL DS:[<&MSVCR71.exit>] ; exit MOV EAX,1 POP ESI POP ECX RETN PUSH cryptex.0040313C ; format = ERROR: Cryptex9 signature in header! CALL DS:[<&MSVCR71.printf>] ; printf ADD ESP,4 PUSH 1 ; status = 1 CALL DS:[<&MSVCR71.exit>] ; exit

standard Normal distribution. Then a pair of correlated random numbers, y1 and y2 , from the standard Normal distribution are y1 = x1 y2 = x1 + 1 2 x2 (17.26)

Listing 6.3 (continued)

In summary, to generate correlated sequences of random numbers when the random variables have standard Normal distributions, one proceeds as follows: 1. 2. 3. 4. Calculate the correlation matrix, K. Perform the Cholesky decomposition to nd S. Generate n uniform random numbers between 0 and 1. Modify each number so that it corresponds to the standard Normal distribution with mean 0 and standard deviation 1. This is one instance of the vector X. 5. Compute the vector Y from Equation (17.23). This is an instance of the correlated variables. 6. To obtain the random variables with the correct means and standard deviations, for each variable compute: zi = zi + zi yi (17.27) The zi comprise one instance of the vector Z of correlated random variables with the desired means and standard deviations. 7. Repeat steps 2 through 6 for each additional randomly generated instance of Z.

It looks as if the function in Listing 6.3 performs some kind of header verification on the archive. It starts out by moving the file pointer to zero (using the SetFilePointer API), and proceeds to read the first 0x28 bytes from the archive file using the ReadFile API. The header data is read into a data structure that is stored at 00406058. It is quite easy to see that this address is essentially a global variable of some sort (as opposed to a heap or stack address), because it is very close to the code address itself. A quick look at the Executable Modules window shows us that the program s executable, Cryptex.exe was loaded into 00400000. This indicates that 00406058 is somewhere within the Cryptex.exe module, probably in the data section (you could verify this by checking the module s data section RVA using an executable dumping tool, but it is quite obvious). The function proceeds to compare the first two DWORDs in the header with the hard-coded values 70597243 and 39586554. If the first two DWORDs don t match these constants, the function jumps to 0040123C and displays the message ERROR: Invalid Cryptex9 signature in file header!. A

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